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Proof step 4 from proof addarray-length-in (conclusion)

⊦ r -- _length ∈ addarray(r0, ty, vals, st) ↔ r = r0 ∨ r -- _length ∈ st

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ r ≠ r0 → (r -- sk ∈ addarray(r0, ty, vals, st) ↔ r -- sk ∈ st)
Proof step 2:
⊦ r -- _length ∈ addarray(r, ty, vals, st)
Proof step 3:
⊦ rk ∈ st → rk ∈ addarray(r, ty, vals, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]