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Proof step 3 from proof addarray-mklist-04 (conclusion)

⊦ 0 ≤ i → addarray(r, mklist(val, n), i, addarray(r, mklist(val, i→n(i)), 0, st)) = addarray(r, val, n→i(n) + i, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
0 ≤ i ⊦ addarray(r, mklist(val, n), i, addarray(r, mklist(val, i→n(i)), 0, st)) = addarray(r, val, n→i(n) + i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j])]]