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Proof step 129 from proof addarray-put-01 (previous step)

i→n(i) = m + 1 ∧ i→n(i) ≠ 0, 0 ≤ i0, i ≤ i0, 0 < i, 0 < i0 ⊦ i = 0, (addarray(r, ty, 1 + i0, st)[r -- i ']) = (mklist(initial_value(ty), i→n(i0))[m])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 128:
i→n(i) = m + 1, 0 ≤ i0, i ≤ i0, 0 < i, 0 < i0 ⊦ i = 0, (addarray(r, ty, 1 + i0, st)[r -- i ']) = (mklist(initial_value(ty), i→n(i0))[m])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i→n(i) = 0 ↔ i = 0])]]