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Proof step 153 from proof addarray-put-01 (previous step)

i < 0 ∨ i0 + j + 1 ≤ i, 0 ≤ i0, 0 ≤ i0 + j, 0 < j ⊦ j = 0, st[r -- i '] = (addarray(r, ty, mklist(initial_value(ty), i→n(j)) + val ' + mklist(initial_value(ty), i→n(i0)), st)[r -- i ']), i = j, ¬ i < 0 ∧ ¬ i0 + j < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 152:
0 ≤ i0, 0 ≤ i0 + j, 0 < j, i < 0 ∨ i0 + j < i ⊦ j = 0, st[r -- i '] = (addarray(r, ty, mklist(initial_value(ty), i→n(j)) + val ' + mklist(initial_value(ty), i→n(i0)), st)[r -- i ']), i = j, ¬ i < 0 ∧ ¬ i0 + j < i

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + 1 ≤ j ↔ i < j], [CSIMPSEQ : ⊦ i + j = j + i])]]