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Proof step 155 from proof addarray-put-01 (previous step)

¬ (0 ≤ i ∧ i < i0 + j + 1), 0 ≤ i0, 0 ≤ i0 + j, 0 < j ⊦ j = 0, (addarray(r, ty, i0 + j + 1, st)[r -- i ']) = (addarray(r, ty, mklist(initial_value(ty), i→n(j)) + val ' + mklist(initial_value(ty), i→n(i0)), st)[r -- i ']), i = j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 154:
0 ≤ i0, 0 ≤ i0 + j, 0 < j ⊦ j = 0, (addarray(r, ty, i0 + j + 1, st)[r -- i ']) = (addarray(r, ty, mklist(initial_value(ty), i→n(j)) + val ' + mklist(initial_value(ty), i→n(i0)), st)[r -- i ']), i = j, ¬ i < 0 ∧ ¬ i0 + j < i

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i < j + 1 ↔ i ≤ j], [CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i])]]