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Proof step 173 from proof addarray-put-01 (previous step)

n = m + 1, i→n(i) = n + i→n(j), 1 < i0 + j, 1 < i, 0 < i, i ≤ j + i0, 0 ≤ i, i ≤ i0 + j, 0 < j, 0 ≤ i0 + j, 0 ≤ i0, 0 < i0, j < i ⊦ j = 0, i = j, initial_value(ty) = (mklist(initial_value(ty), i→n(i0))[m]), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 172:
i→n(i) = (m + 1) + i→n(j), 1 < i0 + j, 1 < i, 0 < i, i ≤ j + i0, 0 ≤ i, i ≤ i0 + j, 0 < j, 0 ≤ i0 + j, 0 ≤ i0, 0 < i0, j < i ⊦ j = 0, i = j, initial_value(ty) = (mklist(initial_value(ty), i→n(i0))[m])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + 1 ≠ 0])]]