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Proof step 195 from proof addarray-put-01 (previous step)

0 ≤ i0 + j, 0 ≤ i0, 0 ≤ j, r0 ≠ r ∨ sk ≠ j ' ⊦ (addarray(r, ty, i0 + j + 1, st)[r0 -- sk]) = (addarray(r, ty, ((j = 0 ⊃ []; mklist(initial_value(ty), i→n(j)))) + val ' + mklist(initial_value(ty), i→n(i0)), st)[r0 -- sk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 102:
⊦ r ≠ r0 → (addarray(r, ty, i, st)[r0 -- sk]) = st[r0 -- sk]
Proof step 103:
⊦ r ≠ r0 → (addarray(r, ty, vals, st)[r0 -- sk]) = st[r0 -- sk]
Proof step 194:
0 ≤ j, 0 ≤ i0, 0 ≤ i0 + j ⊦ sk = j ', (addarray(r, ty, i0 + j + 1, st)[r -- sk]) = (addarray(r, ty, ((j = 0 ⊃ []; mklist(initial_value(ty), i→n(j)))) + val ' + mklist(initial_value(ty), i→n(i0)), st)[r -- sk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]