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Proof step 35 from proof addarray-put-01 (previous step)

r -- i ' ∈ addarray(r, ty, 1 + i0, st), 0 ≤ i0, i < 0 ∨ i0 < i ⊦ i = 0, r -- i ' ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 31:
⊦ r ≠ r0 → (r -- sk ∈ addarray(r0, ty, i, st) ↔ r -- sk ∈ st)
Proof step 34:
¬ r ≠ r, r -- i ' ∈ addarray(r, ty, 1 + i0, st), 0 ≤ i0, i < 0 ∨ i0 < i ⊦ i = 0, r -- i ' ∈ st

Rule argument

[crewrite-arg: in-1dim-01 , F , [st, i, ty, r0, sk, r] → [st, 1 + i0, ty, r, i ', r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, 1 + i0, ty, r, i ', r)]]