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Proof step 3 from proof addarray-put (conclusion)

⊦ rk .ref ≠ r → addarray(r, ty, vals, st[rk, val]) = (addarray(r, ty, vals, st)[rk, val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ rk .ref = r, addarray(r, ty, vals, st[rk, val]) = (addarray(r, ty, vals, st)[rk, val])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]