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Proof step 11 from proof addarray-refs (previous step)

⊦ r0 ∈ addarray(r, initial_value(ty), i, st[r -- _type, typeval(mkarraytype(ty))][r -- _length, intval(i)]) .refs ↔ r0 = r ∨ r0 ∈ st .refs

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ r ∈ st .refs ↔ r ∈ st
Proof step 10:
⊦ r0 ∈ addarray(r, initial_value(ty), i, st[r -- _type, typeval(mkarraytype(ty))][r -- _length, intval(i)]) ↔ r0 = r ∨ r0 ∈ st .refs

Rule argument

[speclemmaarg: ,r ∈ st .refs ↔ r ∈ st ,[st, r] → [addarray (r, initial_value(ty), i, st[r -- _type, typeval(mkarraytype(ty))][r -- _length, intval(i)]), r0] ,F ,storefunsx , ,refs-def ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addarray (r, initial_value(ty), i, st[r -- _type, typeval(mkarraytype(ty))] [r -- _length, intval(i) ]), r0)]]