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Proof step 6 from proof addarray-subset (previous step)

rk ∈ st, newref(r, st) ⊦ r = jvmref, st[rk] = (addarray(r, ty, vals, st)[rk])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ rk .ref ≠ r → (addarray(r, ty, vals, st)[rk]) = st[rk]
Proof step 5:
¬ rk .ref ≠ r, rk ∈ st, newref(r, st) ⊦ r = jvmref, st[rk] = (addarray(r, ty, vals, st)[rk])

Rule argument

[crewrite-arg: add-at-01 , F , [rk, st, vals, ty, r] → [rk, st, vals, ty, r] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (rk, st, vals, ty, r)]]