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Proof step 15 from proof addbar-refval-01 (previous step)

# ints = m + 1, i < n→i(m), 0 ≤ i, ∀ st, r, i, ints0. # ints0 < m + 1 → (0 ≤ i ∧ i < n→i(# ints0) → ints0 = [] ∨ is_bytevalue(addarray(r, byte_type, mkjavavalues(is2bs(ints0)), st)[r -- i '])) ⊦ i = n→i(m), is2bs(ints) = [], ints = [], m = 0, is_bytevalue(addarray(r, byte_type, mkjavavalues(is2bs(ints)) .butlast, st)[r -- i '])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ bytes ≠ [] → mkjavavalues(bytes) .butlast = mkjavavalues(bytes .butlast)
Proof step 14:
is2bs(ints) ≠ [], # ints = m + 1, i < n→i(m), 0 ≤ i, ∀ st, r, i, ints0. # ints0 < m + 1 → (0 ≤ i ∧ i < n→i(# ints0) → ints0 = [] ∨ is_bytevalue(addarray(r, byte_type, mkjavavalues(is2bs(ints0)), st)[r -- i '])) ⊦ i = n→i(m), is2bs(ints) = [], ints = [], m = 0, is_bytevalue(addarray(r, byte_type, mkjavavalues(is2bs(ints) .butlast), st)[r -- i '])

Rule argument

[speclemmaarg: , bytes ≠ [] → mkjavavalues(bytes) .butlast = mkjavavalues(bytes .butlast) ,[bytes] → [is2bs(ints)] ,F ,valuesfuns , ,mkvalues-butlast ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (is2bs(ints))]]