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Proof step 12 from proof at-1dim-other-index-01 (previous step)

j > 0, 0 < j, i < 0 ∨ j ≤ i, ∀ st, val, r, i, j0. i→n(j0) < i→n(j) → (i < 0 ∨ j0 ≤ i → (addarray(r, val, j0, st)[r -- i ']) = st[r -- i ']) ⊦ (addarray(r, val, j - 1, st)[r -- (j - 1) ', val][r -- i ']) = st[r -- i ']

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
0 < j, i < 0 ∨ j ≤ i, ∀ st, val, r, i, j0. i→n(j0) < i→n(j) → (i < 0 ∨ j0 ≤ i → (addarray(r, val, j0, st)[r -- i ']) = st[r -- i ']) ⊦ (addarray(r, val, j - 1, st)[r -- (j - 1) ', val][r -- i ']) = st[r -- i ']

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i > j ↔ j < i])]]