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Proof step 15 from proof at-1dim-other-index-01 (previous step)

i < 0 ∨ j ≤ i, ∀ st, val, r, i, j0. i→n(j0) < i→n(j) → (i < 0 ∨ j0 ≤ i → (addarray(r, val, j0, st)[r -- i ']) = st[r -- i ']) ⊦ (addarray(r, val, j, st)[r -- i ']) = st[r -- i ']

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ i ≤ 0 → addarray(r, val, i, st) = st
Proof step 14:
¬ j ≤ 0, i < 0 ∨ j ≤ i, ∀ st, val, r, i, j0. i→n(j0) < i→n(j) → (i < 0 ∨ j0 ≤ i → (addarray(r, val, j0, st)[r -- i ']) = st[r -- i ']) ⊦ (addarray(r, val, j, st)[r -- i ']) = st[r -- i ']

Rule argument

[crewrite-arg: addarray-base, F, [st, i, val, r] → [st, j, val, r]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, j, val, r)]]