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Proof step 2 from proof at-init (previous step)

is_fskey(sk) ⊦ ((i ' = sk ⊃ val; addarray(r, vals, j, st)[r -- i '])) = (addarray(r, vals, j, st)[r -- i '])

Heuristic if-then-else split applied rule case distinction

And closed the goal!

Rule argument

[CASEDARG : pos: right 1, ()]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ is_fskey(i ')])]]