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Proof step 10 from proof getarray-addarray-03 (previous step)

i1 < 0 ∨ 0 + i1 ≤ i1, 0 ≤ i1, 0 < i1, ∀ st, val, r, i0. i→n(i0) < i→n(i1 + 1) → (0 ≤ i0 → getarray(r, 0, i0, addarray(r, val, i0, st)) = mklist(val, i→n(i0))) ⊦ getarray(r, 0, i1, addarray(r, val, i1, st)) = mklist(val, i→n(i1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
0 ≤ i1, 0 < i1, ∀ st, val, r, i0. i→n(i0) < i→n(i1 + 1) → (0 ≤ i0 → getarray(r, 0, i0, addarray(r, val, i0, st)) = mklist(val, i→n(i0))) ⊦ getarray(r, 0, i1, addarray(r, val, i1, st)) = mklist(val, i→n(i1))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i ≤ i], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + 0 = i], [CSIMPSEQ : ⊦ i < j → ¬ j < i])]]