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Proof step 12 from proof getarray-addarray-05 (previous step)

j > 0, 0 ≤ j, 0 ≤ i, i < j, 0 < j, ∀ st, val, r, i, j0. i→n(j0) < i→n(j) → (i ≤ j0 ∧ 0 ≤ i ∧ 0 ≤ j0 → getarray(r, 0, i, addarray(r, val, j0, st)) = mklist(val, i→n(i))) ⊦ i = j, getarray(r, 0, i, addarray(r, val, j - 1, st)[r -- (j - 1) ', val]) = mklist(val, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 11:
0 ≤ j, 0 ≤ i, i < j, 0 < j, ∀ st, val, r, i, j0. i→n(j0) < i→n(j) → (i ≤ j0 ∧ 0 ≤ i ∧ 0 ≤ j0 → getarray(r, 0, i, addarray(r, val, j0, st)) = mklist(val, i→n(i))) ⊦ i = j, getarray(r, 0, i, addarray(r, val, j - 1, st)[r -- (j - 1) ', val]) = mklist(val, i→n(i))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i > j ↔ j < i])]]