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Proof step 8 from proof getarray-addarray-05 (previous step)

i0 < 0 ∨ 0 + i ≤ i0, 0 ≤ i, i ≤ i0, 0 ≤ i0, ∀ st, val, r, i, j0. i→n(j0) < i→n(i0 + 1) → (i ≤ j0 ∧ 0 ≤ i ∧ 0 ≤ j0 → getarray(r, 0, i, addarray(r, val, j0, st)) = mklist(val, i→n(i))) ⊦ getarray(r, 0, i, addarray(r, val, i0, st)) = mklist(val, i→n(i))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
0 ≤ i, i ≤ i0, 0 ≤ i0, ∀ st, val, r, i, j0. i→n(j0) < i→n(i0 + 1) → (i ≤ j0 ∧ 0 ≤ i ∧ 0 ≤ j0 → getarray(r, 0, i, addarray(r, val, j0, st)) = mklist(val, i→n(i))) ⊦ getarray(r, 0, i, addarray(r, val, i0, st)) = mklist(val, i→n(i))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + 0 = i], [CSIMPSEQ : ⊦ i ≤ j → (¬ ¬ j < i ↔ false)])]]