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Proof step 10 from proof getbar-add-01 (previous step)

j = i0 + 1, 0 < j, ∀ st, vals, ty, i, r0, r, j0. i→n(j0) < i→n(j) → (true → r = r0 ∨ getbytearray(r, i, j0, addarray(r0, ty, vals, st)) = getbytearray(r, i, j0, st)) ⊦ r = r0, st[r -- i '] .byteval ' + getbytearray(r, i + 1, i0, addarray(r0, ty, vals, st)) = getbytearray(r, i, j, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
0 ≤ i0, ∀ st, vals, ty, i, r0, r, j0. i→n(j0) < i→n(i0 + 1) → (true → r = r0 ∨ getbytearray(r, i, j0, addarray(r0, ty, vals, st)) = getbytearray(r, i, j0, st)) ⊦ r = r0, st[r -- i '] .byteval ' + getbytearray(r, i + 1, i0, addarray(r0, ty, vals, st)) = getbytearray(r, i, i0 + 1, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ (~1) < i ↔ 0 ≤ i], [CSIMPSEQ : ⊦ ((* j)) < i0 + ((* j0)) ↔ j - j0 < i0])]]