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Proof step 4 from proof getbar-add-01 (previous step)

¬ 0 < j, ∀ st, vals, ty, i, r0, r, j0. i→n(j0) < i→n(j) → (true → r = r0 ∨ getbytearray(r, i, j0, addarray(r0, ty, vals, st)) = getbytearray(r, i, j0, st)) ⊦ getbytearray(r, i, j, addarray(r0, ty, vals, st)) = getbytearray(r, i, j, st), r = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j ≤ 0, ∀ st, vals, ty, i, r0, r, j0. i→n(j0) < i→n(j) → (true → r = r0 ∨ getbytearray(r, i, j0, addarray(r0, ty, vals, st)) = getbytearray(r, i, j0, st)) ⊦ getbytearray(r, i, j, addarray(r0, ty, vals, st)) = getbytearray(r, i, j, st), r = r0

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i])]]