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Proof step 24 from proof getbar-addbar-02 (previous step)

n < i→n(j), i + j ≤ n→i(# ints), i→n(i) + i→n(j) < # ints, 0 ≤ i, 0 < j ⊦ (mkjavavalues(is2bs(ints))[i→n(i) + n]) .byteval = (is2bs(sublist(i→n(i), i→n(j), ints))[n]), ints = [], j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 14:
⊦ n < # ints → (is2bs(ints)[n]) = i2b(ints[n])
Proof step 17:
¬ n < # sublist(i→n(i), i→n(j), ints), n < i→n(j), i + j ≤ n→i(# ints), i→n(i) + i→n(j) < # ints, 0 ≤ i, 0 < j ⊦ (mkjavavalues(is2bs(ints))[i→n(i) + n]) .byteval = (is2bs(sublist(i→n(i), i→n(j), ints))[n]), ints = [], j = 0
Proof step 23:
n < # sublist(i→n(i), i→n(j), ints), n < i→n(j), i + j ≤ n→i(# ints), i→n(i) + i→n(j) < # ints, 0 ≤ i, 0 < j ⊦ (mkjavavalues(is2bs(ints))[i→n(i) + n]) .byteval = i2b(sublist(i→n(i), i→n(j), ints)[n]), ints = [], j = 0

Rule argument

[speclemmaarg: ,n < # ints → (is2bs(ints)[n]) = i2b(ints[n]) ,[n, ints] → [n, sublist(i→n(i), i→n(j), ints)] ,F ,valuesfuns , ,ints2bytes-at ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (n, sublist(i→n(i), i→n(j), ints))]]