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Proof step 29 from proof getbar-addbar-02 (previous step)

i→n(i) + i→n(j) ≤ # mkjavavalues(is2bs(ints)), 0 ≤ j, 0 ≤ i, i→n(i) + i→n(j) < # ints, i + j ≤ n→i(# ints) ⊦ ints = [], i→n(j) = # sublist(i→n(i), i→n(j), ints) ∧ (n < i→n(j) → (sublist(i→n(i), i→n(j), mkjavavalues(is2bs(ints)))[n]) .byteval = (is2bs(sublist(i→n(i), i→n(j), ints))[n]))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
0 ≤ j, 0 ≤ i, i→n(i) + i→n(j) < # ints, i + j ≤ n→i(# ints) ⊦ ints = [], i→n(j) = # sublist(i→n(i), i→n(j), ints) ∧ (n < i→n(j) → (sublist(i→n(i), i→n(j), mkjavavalues(is2bs(ints)))[n]) .byteval = (is2bs(sublist(i→n(i), i→n(j), ints))[n]))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ m < n → m ≤ n], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ # is2bs(ints) = # ints], [CSIMPSEQ : ⊦ # mkjavavalues(bytes) = # bytes])]]