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Proof step 37 from proof getbar-addbar-02 (conclusion)

⊦ 0 ≤ i ∧ 0 ≤ j ∧ i→n(i) + i→n(j) < # ints → getbytearray(r, i, j, addbytearray(r, ints, st)) = is2bs(sublist(i→n(i), i→n(j), ints))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 36:
0 ≤ j, 0 ≤ i, i→n(i) + i→n(j) < # ints ⊦ getbytearray(r, i, j, addbytearray(r, ints, st)) = is2bs(sublist(i→n(i), i→n(j), ints)), ints = []

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ # ints = 0 ↔ ints = []], [CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ m < n → n ≠ 0])]]