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Proof step 8 from proof getbar-addbar-02 (previous step)

0 ≤ j, 0 ≤ i, i→n(i) + i→n(j) < # ints, n→i(# ints) < i + j, 0 < i + j ⊦ bytevalues(getarray(r, i, j, addarray(r, byte_type, mkjavavalues(is2bs(ints)), st))) = is2bs(sublist(i→n(i), i→n(j), ints)), ints = []

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
0 ≤ i ⊦ n→i(n) < i ↔ n < i→n(i)
Proof step 7:
0 ≤ i + j, 0 ≤ j, 0 ≤ i, i→n(i) + i→n(j) < # ints, # ints < i→n(i + j), 0 < i + j ⊦ bytevalues(getarray(r, i, j, addarray(r, byte_type, mkjavavalues(is2bs(ints)), st))) = is2bs(sublist(i→n(i), i→n(j), ints)), ints = []

Rule argument

[speclemmaarg: 0 ≤ i ,n→i(n) < ((* i)) ↔ n < i→n(i) ,[i, n] → [i + j, # ints] ,F ,intnat , ,num-n2i-ls ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ ¬ i ≤ j ↔ j < i], [CSIMPSEQ : ⊦ 0 ≤ i ∧ 0 ≤ j → ¬ i + j < 0], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j = j + i])], [EXTRATERMS : (i + j, # ints)]]