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Proof step 24 from proof getbytearray-addarray-this (previous step)

0 ≤ i ⊦ getbytearray(r, addarray(r, byte_type, i, st)) = mklist(i2b(0), i→n(i))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ bytes = bytes0 ↔ # bytes = # bytes0 ∧ (∀ n. n < # bytes → bytes[n] = bytes0[n])
Proof step 23:
0 ≤ i ⊦ # getbytearray(r, addarray(r, byte_type, i, st)) = # mklist(i2b(0), i→n(i)) ∧ (∀ n. n < # getbytearray(r, addarray(r, byte_type, i, st)) → (getbytearray(r, addarray(r, byte_type, i, st))[n]) = (mklist(i2b(0), i→n(i))[n]))

Rule argument

[speclemmaarg: , bytes = bytes0 ↔ # bytes = # bytes0 ∧ (∀ n. n < # bytes → bytes[n] = bytes0[n]) ,[bytes0, bytes] → [mklist(i2b(0), i→n(i)), getbytearray(r, addarray(r, byte_type, i, st))] ,F ,list-del ,bytelist ,extension ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (mklist(i2b(0), i→n(i)), getbytearray(r, addarray(r, byte_type, i, st)))]]