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Proof step 3 from proof in-1dim-05 (conclusion)

⊦ r ∈ addarray(r, ty0, i, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ addarray(r, ty, i, st) = addarray(r, initial_value(ty), i, st[r -- _type, typeval(mkarraytype(ty))][r -- _length, intval(i)])
Proof step 2:
⊦ r ∈ addarray(r, val, i, st) ↔ 0 < i ∨ r ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ∈ st[r0 -- sk, val] ↔ r = r0 ∨ r ∈ st], [CSIMPSEQ : ⊦ ¬ i < j ↔ j ≤ i])]]