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Proof step 4 from proof in-1dim-09 (previous step)

r -- sk ∈ st, r ∈ st ⊦ r -- sk ∈ addarray(r0, val, i, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 3:
⊦ rk ∈ st → rk ∈ addarray(r, val, i, st)

Rule argument

[crewrite-arg: in-1dim-13 , F , [st, i, val, r, rk] → [st, i, val, r0, r -- sk] ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (st, i, val, r0, r -- sk)]]