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Proof step 11 from proof in-1dim-13 (previous step)

r0 -- sk ∈ st ⊦ r0 -- sk ∈ addarray(r, val, i, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
r0 -- sk ∈ st, r0 ∈ st ⊦ r0 -- sk ∈ addarray(r, val, i, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ r -- sk ∈ st → r ∈ st])]]