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Proof step 3 from proof in-1dim-17 (previous step)

is_fskey(sk) ⊦ r -- sk ∈ addarray(r0, val, i, st) ↔ r -- sk ∈ st

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_fskey(sk) ↔ (∃ fs. sk = fs ')
Proof step 2:
⊦ r -- fs ' ∈ addarray(r0, val, i, st) ↔ r -- fs ' ∈ st

Rule argument

[speclemmaarg: ,is_fskey(sk) ↔ (∃ fs. sk = fs ') ,[sk] → [sk] ,F ,storekey , ,ex-03 ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (sk)]]