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Proof step 16 from proof in-1dim-other-index-01 (conclusion)

⊦ i < 0 ∨ j ≤ i → (r -- i ' ∈ addarray(r, val, j, st) ↔ r -- i ' ∈ st)

User applied rule induction

And obtained the following new goals

Proof step 15:
true, ∀ st, val, r, i, j0. i→n(j0) < i→n(j) → (true → (i < 0 ∨ j0 ≤ i → (r -- i ' ∈ addarray(r, val, j0, st) ↔ r -- i ' ∈ st))) ⊦ i < 0 ∨ j ≤ i → (r -- i ' ∈ addarray(r, val, j, st) ↔ r -- i ' ∈ st)

Rule argument

[INDHYPARG : [STANDARDINDUCTIONTYPE : ], true, false, i→n(j), [] → [], <]

Additional information

[[CONCRETESIMPRULES : ([CSIMPLESSPRED : <])], [EXTRATERMS : (i→n(j))]]