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Proof step 9 from proof in-1dim-other (previous step)

r0 -- sk ∈ addarray(r0, ty, j, st), is_indexkey(sk), sk .index < 0 ∨ j ≤ sk .index ⊦ r0 -- sk ∈ st

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 8:
sk = i ', r0 -- sk ∈ addarray(r0, ty, j, st), is_indexkey(sk), i < 0 ∨ j ≤ i ⊦ r0 -- sk ∈ st

Rule argument

[speclemmaarg: ,is_indexkey(sk) → (i = sk .index ↔ sk = i ') ,[sk, i] → [sk, i] ,T ,storekey , ,elim-04 ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPELIM : ⊦ is_indexkey(sk) → (i = sk .index ↔ sk = i ')])], [EXTRATERMS : (sk, i)]]