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Proof step 3 from proof in-1init-01 (previous step)

∀ r, r0, j, st. r = r0 ∨ (r ∈ addarray(r0, vals0, j, st) ↔ r ∈ st) ⊦ r = r0, r ∈ addarray(r0, vals0, j + 1, st) ↔ r ∈ st

User applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 1, [extquanttermlist: (r, r0, j + 1, st) abort:F , discard:T , computed:T ]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, r0, j + 1, st)]]