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Proof step 4 from proof in-init-03 (previous step)

r -- fs ' ∈ addarray(r0, vals0, j + 1, st), r ∈ (addarray(r0, vals0, j + 1, st)[r0 -- j ', val]), r ∈ addarray(r0, vals0, j + 1, st), ∀ r, fs, r0, j, st. r -- fs ' ∈ addarray(r0, vals0, j, st) ∧ r ∈ addarray(r0, vals0, j, st) → r -- fs ' ∈ st ⊦ r -- fs ' ∈ st

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

[EXRARG : pos: left 4, [QUANTTERMLIST : (r, fs, r0, j + 1, st)]]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (r, fs, r0, j + 1, st)]]