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Proof step 4 from proof in-init-08 (previous step)

∀ rk, st, r, j. rk ∈ st → rk ∈ addarray(r, vals0, j, st), rk ∈ st ⊦ rk ∈ addarray(r, val + vals0, j, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ addarray(r, val ' + vals, i, st) = (addarray(r, vals, i + 1, st)[r -- i ', val])
Proof step 3:
rk ∈ st, ∀ rk, st, r, j. rk ∈ st → rk ∈ addarray(r, vals0, j, st) ⊦ rk = r -- j ', rk ∈ addarray(r, vals0, j + 1, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st[rk0, val] ↔ rk = rk0 ∨ rk ∈ st], [CSIMPSEQ : ⊦ (vals + vals0) + vals1 = vals + vals0 + vals1], [CSIMPSEQ : ⊦ val + vals = val ' + vals])]]