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Proof step 6 from proof init-switch (previous step)

is_fskey(sk) ⊦ ¬ is_indexkey(sk), sk = i ', (addarray(r, vals0, i + 1, st[r -- sk, val0])[r -- i ', val]) = (addarray(r, vals0, i + 1, st)[r -- sk, val0][r -- i ', val])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
is_fskey(sk), is_indexkey(sk) ⊦ (addarray(r, vals0, i + 1, st[r -- sk, val0])[r -- i ', val]) = (addarray(r, vals0, i + 1, st)[r -- sk, val0][r -- i ', val]), sk = i '

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]