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Proof step 3 from proof is_array-1dim (conclusion)

⊦ r ≠ r0 → (is_arrayref(r, i, addarray(r0, ty0, i0, st)) ↔ is_arrayref(r, i, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 1:
⊦ addarray(r, ty, i, st) = addarray(r, initial_value(ty), i, st[r -- _type, typeval(mkarraytype(ty))][r -- _length, intval(i)])
Proof step 2:
⊦ r ≠ r0 → (is_arrayref(r, i, addarray(r0, val0, i0, st)) ↔ is_arrayref(r, i, st))

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ r ≠ r0 → ( is_arrayref (r, i, st[r0 -- sk, val0]) ↔ is_arrayref(r, i, st))], [CSIMPSEQ : ⊦ is_arrayref (r, i, st[r0 -- _length, val]) ↔ is_arrayref(r, i, st)])]]