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Proof step 6 from proof is_array-addarray-01 (previous step)

is_array(str, r, addarray(r, mkclasstype(class), vals, st)), n < # vals, is_referencevalue(addarray(r, mkclasstype(class), vals, st)[r -- n→i(n) ']) ⊦ vals = [], is_referencevalue(vals[n])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 5:
0 ≤ i, i < n→i(# vals) ⊦ (addarray(r, ty, vals, st)[r -- ((* i)) ']) = vals[i→n(i)]

Rule argument

[crewrite-arg: add-at-ok-01 , F , [i, st, vals, ty, r] → [n→i(n), st, vals, mkclasstype(class), r] ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ i→n(n→i(n)) = n], [CSIMPSEQ : ⊦ 0 ≤ n→i(n)], [CSIMPSEQ : ⊦ n→i(m) < n→i(n) ↔ m < n], [CSIMPSEQ : ⊦ ¬ m < n ↔ n ≤ m], [CSIMPSEQ : ⊦ m < n → (n ≤ m ↔ false)])], [EXTRATERMS : (n→i(n), st, vals, mkclasstype(class), r)]]