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Proof step 8 from proof is_array-addarray-01 (previous step)

is_array(str, r, addarray(r, mkclasstype(class), vals, st)), n < # vals ⊦ vals = [], is_referencevalue(vals[n])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ ¬ is_referencevalue(st[r -- i ']) ∧ is_reftype(st[r -- _type] .type .type) ∧ 0 ≤ i ∧ i < st[r -- _length] .intval → ¬ is_array(str, r, st)
Proof step 7:
¬ ( ¬ is_referencevalue(addarray(r, mkclasstype(class), vals, st)[r -- n→i(n) ']) ∧ is_reftype((addarray(r, mkclasstype(class), vals, st)[r -- _type]) .type .type) ∧ 0 ≤ n→i(n) ∧ n→i(n) < (addarray(r, mkclasstype(class), vals, st)[r -- _length]) .intval), is_array(str, r, addarray(r, mkclasstype(class), vals, st)), n < # vals ⊦ vals = [], is_referencevalue(vals[n])

Rule argument

[speclemmaarg: , ¬ is_referencevalue(st[r -- i ']) ∧ is_reftype(st[r -- _type] .type .type) ∧ 0 ≤ i ∧ i < st[r -- _length] .intval → ¬ is_array(str, r, st) ,[st, r, i, str] → [addarray(r, mkclasstype(class), vals, st), r, n→i(n), str] ,F ,okfuns , ,is_array-norefval ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addarray(r, mkclasstype(class), vals, st), r, n→i(n), str)]]