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Proof step 9 from proof is_array-addarray-prim (previous step)

0 ≤ j, j < n→i(# vals), is_primtype(ty), vals[i→n(j)] ∈ vals → okprimtype(vals[i→n(j)], ty) ⊦ ty = void_type, ty = abstract_type, r = jvmref, vals = [], okval(vals[i→n(j)], ty), is_array(r, addarray(r, ty, vals, st))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ m < # vals → (¬ vals[m] ∈ vals ↔ false)
Proof step 7:
¬ i→n(j) < # vals, 0 ≤ j, j < n→i(# vals), is_primtype(ty), vals[i→n(j)] ∈ vals → okprimtype(vals[i→n(j)], ty) ⊦ ty = void_type, ty = abstract_type, r = jvmref, vals = [], okval(vals[i→n(j)], ty), is_array(r, addarray(r, ty, vals, st))
Proof step 8:
i→n(j) < # vals, 0 ≤ j, j < n→i(# vals), is_primtype(ty), true → okprimtype(vals[i→n(j)], ty) ⊦ ty = void_type, ty = abstract_type, r = jvmref, vals = [], okval(vals[i→n(j)], ty), is_array(r, addarray(r, ty, vals, st))

Rule argument

[speclemmaarg: ,m < # vals → (¬ vals[m] ∈ vals ↔ false) ,[m, vals] → [i→n(j), vals] ,F ,list-del ,javavalues ,get-in ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (i→n(j), vals)]]