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Proof step 5 from proof is_array-init-01 (previous step)

∀ j0. ¬ j0 < 0 ∧ ¬ i ≤ j0 → r -- j0 ' ∈ st ⊦ ∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st, r = r0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
j < i, 0 ≤ j, 0 < i, ∀ j0. ¬ j0 < 0 ∧ ¬ i ≤ j0 → r -- j0 ' ∈ st ⊦ r = r0, r -- j ' ∈ st

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j])]]