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Proof step 7 from proof is_obj-addarray (previous step)

⊦ r = r0, is_obj(str, r, addarray(r0, ty0, vals, st)) ↔ is_obj(str, r, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_obj(str, r, st) ↔ class+∃(str, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st)
Proof step 6:
⊦ r = r0, class+∃(str, (addarray(r0, ty0, vals, st)[r -- _type]) .type .class) ∧ ¬ is_abstract((addarray(r0, ty0, vals, st)[r -- _type]) .type .class) ∧ is_obj(r, addarray(r0, ty0, vals, st)) ↔ is_obj(str, r, st)

Rule argument

[speclemmaarg: , is_obj(str, r, st) ↔ class+∃(str, st[r -- _type] .type .class) ∧ ¬ is_abstract(st[r -- _type] .type .class) ∧ is_obj(r, st) ,[st, r, str] → [addarray(r0, ty0, vals, st), r, str] ,F ,addfuns , ,is-real-object-def ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addarray(r0, ty0, vals, st), r, str)]]