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Proof step 3 from proof isarray-1dim (conclusion)

⊦ is_arrayref(r, i, addarray(r, ty, i, st))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 1:
⊦ is_arrayref(r, i, st) ↔ (∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st)
Proof step 2:
⊦ 0 ≤ j ∧ j < i → r -- j ' ∈ addarray(r, ty, i, st)

Rule argument

[speclemmaarg: ,is_arrayref(r, i, st) ↔ (∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ st) ,[st, i, r] → [addarray(r, ty, i, st), i, r] ,F ,storearrays , ,is_arrayref ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addarray(r, ty, i, st), i, r)]]