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Proof step 27 from proof isarray-addarray-01 (previous step)

is_array(r1, addarray(r0, ty, vals, st)) ⊦ r1 = r0, is_array(r1, st)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 2:
⊦ is_array(r, st) ↔ r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_arraytype(st[r -- _type] .type) ∧ okarray(r, st[r -- _type] .type .type, st)
Proof step 26:
r1 ≠ jvmref ∧ r1 -- _type ∈ addarray(r0, ty, vals, st) ∧ is_typevalue(addarray(r0, ty, vals, st)[r1 -- _type]) ∧ is_arraytype((addarray(r0, ty, vals, st)[r1 -- _type]) .type) ∧ okarray(r1, (addarray(r0, ty, vals, st)[r1 -- _type]) .type .type, addarray(r0, ty, vals, st)) ⊦ r1 = r0, is_array(r1, st)

Rule argument

[speclemmaarg: , is_array(r, st) ↔ r ≠ jvmref ∧ r -- _type ∈ st ∧ is_typevalue(st[r -- _type]) ∧ is_arraytype(st[r -- _type] .type) ∧ okarray(r, st[r -- _type] .type .type, st) ,[st, r] → [addarray(r0, ty, vals, st), r1] ,F ,okfuns , ,is-any-array ]

Additional information

[[CONCRETESIMPRULES : ()], [EXTRATERMS : (addarray(r0, ty, vals, st), r1)]]