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Proof step 4 from proof isarray-init-01 (previous step)

i < n→i(# vals) ⊦ ∀ j. 0 ≤ j ∧ j < i → r -- j ' ∈ addarray(r, ty, vals, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j < i, i < n→i(# vals), 0 ≤ j, j < n→i(# vals), 0 < i ⊦ # vals = 1, vals = [], r -- j ' ∈ addarray(r, ty, vals, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ 0 < n ↔ n ≠ 0], [CSIMPSEQ : ⊦ # vals = 0 ↔ vals = []], [CSIMPSEQ : ⊦ 1 < m ↔ ¬ (m = 0 ∨ m = 1)], [CSIMPSEQ : 0 ≤ i ⊦ ((* i)) < n→i(n) ↔ i→n(i) < n], [CSIMPFORWARD : ⊦ i ≤ j ∧ j < j0 → i < j0], [CSIMPFORWARD : ⊦ i < j ∧ 0 < i → 0 < j ∧ 1 < j], [CSIMPFORWARD : ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j], [CSIMPFORWARD : ⊦ i < i0 ∧ i0 < i1 → i < i1], [CSIMPFORWARD : ⊦ i < j ∧ 0 ≤ i → 0 < j])]]