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Proof step 28 from proof move-initvals (previous step)

vals ≠ [], 0 ≤ i, i→n(i) < # vals, ∀ val, st, ty, r, i, vals0. # vals0 < # vals → (true → (0 ≤ i ∧ i→n(i) < # vals0 → (addarray(r, ty, vals0, st)[r -- i ', val]) = addarray(r, ty, vals0[i→n(i), val], st))) ⊦ (addarray(r, ty, vals .butlast, st)[r -- n→i((# vals) -1) ', vals .last][r -- _length, intval(n→i(# vals))][r -- i ', val]) = addarray(r, ty, vals[i→n(i), val], st), vals = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
0 ≤ i, i→n(i) < # vals, ∀ val, st, ty, r, i, vals0. # vals0 < # vals → (true → (0 ≤ i ∧ i→n(i) < # vals0 → (addarray(r, ty, vals0, st)[r -- i ', val]) = addarray(r, ty, vals0[i→n(i), val], st))) ⊦ vals = [], (addarray(r, ty, vals .butlast, st)[r -- n→i(# vals - 1) ', vals .last][r -- _length, intval(n→i(# vals))][r -- i ', val]) = addarray(r, ty, vals[i→n(i), val], st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ n -1 = n - 1])]]