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Proof step 6 from proof newref-1init (conclusion)

⊦ vals ≠ [] → (newref(r0, addarray(r, vals, j, st)) ↔ r ≠ r0 ∧ newref(r0, st))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
⊦ vals = [], newref(r0, addarray(r, vals, j, st)) ↔ r ≠ r0 ∧ newref(r0, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]