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Proof step 28 from proof putByteArray-vals-addarray-01 (previous step)

i→n(i0) = n + # bytes, 0 < n→i(# bytes) + i1, i0 < n→i(# bytes) + i1, 0 ≤ i1, 0 ≤ j, 0 ≤ n→i(# bytes) + i1, 0 ≤ j + n→i(# bytes) + i1, 0 < n→i(# bytes) + j, i0 < n→i(# bytes), 0 ≤ i0 + j, 0 ≤ i0, # bytes ≤ i→n(i0) ⊦ bytes = [], (mkjavavalues(bytes)[i→n(i0)]) = (mklist(initial_value(byte_type), i→n(i1))[n])

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 27:
0 ≤ i ⊦ i→n(i) = ((* m)) ↔ i = n→i(m)

Rule argument

[speclemmaarg: 0 ≤ i ,i→n(i) = ((* m)) ↔ i = n→i(m) ,[m, i] → [n + # bytes, i0] ,F ,intnat , ,num-i2n-eq ]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ n→i(m + n) = n→i(m) + n→i(n)], [CSIMPSEQ : ⊦ (m + n0) + n1 = m + n0 + n1], [CSIMPSEQ : ⊦ m + n = n + m], [CSIMPSEQ : ⊦ i + j + i0 = (i + j) + i0], [CSIMPSEQ : ⊦ i + j = j + i], [CSIMPSEQ : ⊦ i + j < i + i0 ↔ j < i0], [CSIMPSEQ : ⊦ i + j < j ↔ i < 0], [CSIMPSEQ : ⊦ ¬ n→i(n) < 0])], [EXTRATERMS : (n + # bytes, i0)]]