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Proof step 18 from proof putarray-add-same (previous step)

r ≠ r0 ∨ r = r0 ∧ is_fskey(sk) ∧ sk ≠ _length ∧ sk ≠ _type ∨ r = r0 ∧ is_indexkey(sk) ∧ (sk .index < 0 ∨ n→i(# vals) ≤ sk .index) ⊦ r0 -- sk ∈ st ∨ r0 = r ∧ is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < n→i(# vals) ↔ r0 -- sk ∈ addarray(r, ty, vals, st)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
⊦ r ≠ r0 → (r -- sk ∈ addarray(r0, ty, vals, st) ↔ r -- sk ∈ st)
Proof step 17:
is_indexkey(sk) ∧ (sk .index < 0 ∨ n→i(# vals) ≤ sk .index) ∨ is_fskey(sk) ∧ sk ≠ _length ∧ sk ≠ _type ⊦ r0 -- sk ∈ st ∨ is_indexkey(sk) ∧ 0 ≤ sk .index ∧ sk .index < n→i(# vals) ↔ r0 -- sk ∈ addarray(r0, ty, vals, st)

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]