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Proof step 50 from proof putarray-add-same (previous step)

⊦ ∀ rk. (rk ∈ putArray(vals, r, addarray(r, ty, n→i(# vals), st)) ↔ rk ∈ addarray(r, ty, vals, st)) ∧ (putArray(vals, r, addarray(r, ty, n→i(# vals), st))[rk]) = (addarray(r, ty, vals, st)[rk])

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 49:
⊦ (rk ∈ putArray(vals, r, addarray(r, ty, n→i(# vals), st)) ↔ rk ∈ addarray(r, ty, vals, st)) ∧ (putArray(vals, r, addarray(r, ty, n→i(# vals), st))[rk]) = (addarray(r, ty, vals, st)[rk])

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ()]]