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Proof step 114 from proof putarray-addarray-01 (previous step)

0 ≤ i, 0 ≤ i0 + n→i(# vals), 0 ≤ i0 + i + n→i(# vals), 0 < i0 ⊦ ∀ rk. ( rk ∈ putArray(vals, r, i, addarray(r, ty, i0 + i + n→i(# vals), st)) ↔ rk ∈ (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals + mklist(initial_value(ty), i→n(i0)), st) [r -- _length, intval(i0 + i + n→i(# vals)) ] )) ∧ (putArray(vals, r, i, addarray(r, ty, i0 + i + n→i(# vals), st))[rk]) = (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals + mklist(initial_value(ty), i→n(i0)), st)[r -- _length, intval(i0 + i + n→i(# vals))] [rk ] )

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 113:
0 ≤ i, 0 ≤ i0 + n→i(# vals), 0 ≤ i0 + i + n→i(# vals), 0 < i0 ⊦ ( rk ∈ putArray(vals, r, i, addarray(r, ty, i0 + i + n→i(# vals), st)) ↔ rk = r -- _length ∨ rk ∈ addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals + mklist(initial_value(ty), i→n(i0)), st)) ∧ (putArray(vals, r, i, addarray(r, ty, i0 + i + n→i(# vals), st))[rk]) = (addarray(r, ty, mklist(initial_value(ty), i→n(i)) + vals + mklist(initial_value(ty), i→n(i0)), st)[r -- _length, intval(i0 + i + n→i(# vals))] [rk ] )

Rule argument

[emptyarg]

Additional information

[[CONCRETESIMPRULES : ([CSIMPSEQ : ⊦ rk ∈ st[rk0, val] ↔ rk = rk0 ∨ rk ∈ st], [CSIMPSEQ : ⊦ i + j = j + i])]]